## Set .union() Operation - Python HackerRank Solution

Hello Friends, How are you? Today I am going to solve the

**HackerRank Set .union() Operation Problem in Python**with a very easy explanation. In this article, you will get one or more approaches to solving this problem. So let's start-**{tocify} $title={Table of Contents}**

### HackerRank Python Set .union() Operation Solution - Problem Statement

**.union()**

The .union() operator returns the union of a set and the set of elements in an iterable.

Sometimes, the | operator is used in place of .union() operator, but it operates only on the set of elements in set.

Set is immutable to the .union() operation (or | operation).

**Example**

>>> s = set("Hacker") >>> print s.union("Rank") set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n']) >>> print s.union(set(['R', 'a', 'n', 'k'])) set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n']) >>> print s.union(['R', 'a', 'n', 'k']) set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n']) >>> print s.union(enumerate(['R', 'a', 'n', 'k'])) set(['a', 'c', 'r', 'e', (1, 'a'), (2, 'n'), 'H', 'k', (3, 'k'), (0, 'R')]) >>> print s.union({"Rank":1}) set(['a', 'c', 'r', 'e', 'H', 'k', 'Rank']) >>> s | set("Rank") set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n']) {codeBox}

**Task**

The students of District College have subscriptions to English and French newspapers. Some students have subscribed only to English, some have subscribed to only French and some have subscribed to both newspapers.

You are given two sets of student roll numbers. One set has subscribed to the English newspaper, and the other set is subscribed to the French newspaper. The same student could be in both sets. Your task is to find the total number of students who have subscribed to at least one newspaper.

**Input Format**

The first line contains an integer, n, the number of students who have subscribed to the English newspaper.

The second line contains n space-separated roll numbers of those students.

The third line contains b, the number of students who have subscribed to the French newspaper.

The fourth line contains b space-separated roll numbers of those students.

**Constraints**

0 < total number of students in college < 1000

**Output Format:**

Output the total number of students who have at least one subscription.

**Sample Input 0**

9 1 2 3 4 5 6 7 8 9 9 10 1 2 3 11 21 55 6 8 {codeBox}

**Sample Output 0**

13 {codeBox}

**Explanation:**

Roll numbers of students who have at least one subscription: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 21 and 55. Roll numbers: 1, 2, 3, 6 and 8 are in both sets so they are only counted once. Hence, the total is 13 students.

### Python Set .union() Operation - Hacker Rank Solution

**Approach I: Set .union() Operation HackerRank Python Solution**

```
# ========================
# Information
# ========================
# Name: Set .union() Operation in Python HackerRank
# Direct Link: https://www.hackerrank.com/challenges/py-set-union/problem
# Difficulty: Easy
# Max Score: 10
# Language: Pypy 3
# ========================
# Solution Start
# ========================
#Set .union() Operation in Python - Hacker Rank Solution
# Enter your code here. Read input from STDIN. Print output to STDOUT
N1 = int(input())
storage1 = set(input().split());
N2 = int(input())
storage2 = set(input().split());
storage3 = storage1.union(storage2)
print(len(storage3))
#Set .union() Operation in Python - Hacker Rank Solution END
# MyEduWaves
```

**Disclaimer:**The above Problem (

**Python Set .union() Operation**) is generated by

**Hackerrank**but the Solution is Provided by

**MyEduWaves**. This tutorial is only for Educational and Learning purposes. Authority if any queries regarding this post or website fill out the contact form.

I hope you have understood the solution to this HackerRank Problem. All these three solutions will pass all the test cases. Now visit

**Python Set .union() Operation Hackerrank Problem**and try to solve it again.**All the Best!**

Tags:
HackerRank Python