Set Mutations in Python - HackerRank Solution

Set Mutations - Python HackerRank Solution

Hello Friends, How are you? Today I am going to solve the HackerRank Set Mutations Problem in Python with a very easy explanation. In this article, you will get one or more approaches to solving this problem. So let's start-

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Default Arguments Python HackerRank Solution

HackerRank Python Set Mutations Solution - Problem Statement

We have seen the applications of union, intersection, difference and symmetric difference operations, but these operations do not make any changes or mutations to the set.

We can use the following operations to create mutations to a set: 

.update() or |=
Update the set by adding elements from an iterable/another set.

>>> H = set("Hacker") >>> R = set("Rank") >>> H.update(R) >>> print H set(['a', 'c', 'e', 'H', 'k', 'n', 'r', 'R']) {codeBox}

.intersection_update() or &=
Update the set by keeping only the elements found in it and an iterable/another set.

>>> H = set("Hacker") >>> R = set("Rank") >>> H.intersection_update(R) >>> print H set(['a', 'k']) {codeBox}

.difference_update() or -=
Update the set by removing elements found in an iterable/another set.

>>> H = set("Hacker") >>> R = set("Rank") >>> H.difference_update(R) >>> print H set(['c', 'e', 'H', 'r']) {codeBox}

.symmetric_difference_update() or ^=
Update the set by only keeping the elements found in either set, but not in both.

>>> H = set("Hacker") >>> R = set("Rank") >>> H.symmetric_difference_update(R) >>> print H set(['c', 'e', 'H', 'n', 'r', 'R']) {codeBox}

Task

You are given a set A and N number of other sets. These N number of sets have to perform some specific mutation operations on set A.
Your task is to execute those operations and print the sum of elements from set A.

Input Format

The first line contains the number of elements in set A.
The second line contains the space-separated list of elements in set A.
The third line contains integer N, the number of other sets.
The next 2* N lines are divided into N parts containing two lines each.
The first line of each part contains the space-separated entries of the operation name and the length of the other set.
The second line of each part contains a space-separated list of elements in the other set.

Constraints

0 <  len(set(A)) < 1000
0 < len(otherSets) < 1000
0 < N < 100

Output Format:

Output the sum of elements in set A.

Sample Input 0

16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 24 52 4 intersection_update 10 2 3 5 6 8 9 1 4 7 11 update 2 55 66 symmetric_difference_update 5 22 7 35 62 58 difference_update 7 11 22 35 55 58 62 66 {codeBox}

Sample Output 0

38 {codeBox}

Explanation

After the first operation, (intersection_update operation), we get:
set A = set([1, 2, 3, 4, 5, 6, 7, 8, 9, 11])
After the second operation, (update operation), we get:
set A = set([1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 55, 66])
After the third operation, (symmetric_difference_update operation), we get:
set A = set([1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 35, 55, 58, 62, 66])
After the fourth operation, ( difference_update operation), we get:
set A = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
The sum of elements in set A after these operations is 38.

Python Set Mutations - Hacker Rank Solution

Approach I: Set Mutations HackerRank Python Solution
# ========================
#       Information
# ========================

# Name: Set Mutations in Python HackerRank
# Direct Link: https://www.hackerrank.com/challenges/py-set-mutations/problem
# Difficulty: Easy
# Max Score: 10
# Language: Pypy 3

# ========================
#         Solution Start
# ========================

#Set Mutations in Python - Hacker Rank Solution
   
# Enter your code here. Read input from STDIN. Print output to STDOUT
len_set = int(input())

storage = set(map(int, input().split()))

op_len = int(input())

for i in range(op_len):
    operation = input().split()
    if operation[0] == 'intersection_update':
        temp_storage = set(map(int, input().split()))
        storage.intersection_update(temp_storage)
    elif operation[0] == 'update':
        temp_storage = set(map(int, input().split()))
        storage.update(temp_storage)
    elif operation[0] == 'symmetric_difference_update':
        temp_storage = set(map(int, input().split()))
        storage.symmetric_difference_update(temp_storage)
    elif operation[0] == 'difference_update':
        temp_storage = set(map(int, input().split()))
        storage.difference_update(temp_storage)
    else :
        assert False

print(sum(storage))
   
#Set Mutations in Python - Hacker Rank Solution END
# MyEduWaves


Disclaimer: The above Problem ( Python Set Mutations ) is generated by Hackerrank but the Solution is Provided by MyEduWaves. This tutorial is only for Educational and Learning purposes. Authority if any queries regarding this post or website fill out the contact form.

I hope you have understood the solution to this HackerRank Problem. All these three solutions will pass all the test cases. Now visit Python Set Mutations Hackerrank Problem and try to solve it again.

All the Best!

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