# Merge the Tools! HackerRank Python Solutions

## Merge the Tools! - Python HackerRank Solution

Hello Friends, How are you? Today I am going to solve the HackerRank Merge the Tools! A problem in Python with a very easy explanation. In this article, you will get more than one approach to solving this problem. So let's start-

### HackerRank Python Merge the Tools Solution - Problem Statement

Consider the following:

A string, s, of length n where s = c0c1. . . . cn-1.

An integer, k, where k is a factor of n.

We can split s into n/k substrings where each substring, ti, consists of a contiguous block of k characters in s. Then, use each ti to create string ui such that:

The characters in ui are a subsequence of the characters in ti.

Any repeat occurrence of a character is removed from the string such that each character in ui occurs exactly once. In other words, if the character at some index j in ti occurs at a previous index < j in ti, then do not include the character in string ui.

Given s and k, print n/k lines where each line i denotes string ui.

Example

k = 3

There are three substrings of length 3 to consider: ‘AAA’, ‘BCA’ and ‘DDE’. The first substring is all ‘A’ characters, so u1 = ‘A’. The second substring has all distinct characters, so u2 = ‘BCA’. The third substring has 2 different characters, so u3 = ‘DE’. Note that a subsequence maintains the original order of characters encountered. The order of characters in each subsequence shown is important.

Function Description

Complete the merge_the_tools function in the editor below.

merge_the_tools has the following parameters:

string s: the string to analyze
int k: the size of substrings to analyze
Prints
Print each subsequence on a new line. There will be n/k of them. No return value is expected.

Input Format

The first line contains a single string, s.

The second line contains an integer, k, the length of each substring.

Constraints

• 1 <= n <= 10^4, where n is the length of s
• 1 <= k <= n
• It is guaranteed that n is a multiple of k.

Sample Input 0

STDIN Function ----- -------- AABCAAADA s = 'AABCAAADA' 3 k = 3 {codeBox}

Sample Output 0

Explanation 0

Split s into n/k = 9/3 = 3 equal parts of length k = 3. Convert each ti to ui by removing any subsequent occurrences of non-distinct characters in ti:

t0 = “AAB” – u0 = “AB”
t1 = “CAA” – u1 = “CA”
Print each ui on a new line.

### Merge the Tools in Python - Hacker Rank Solution

1st Approach: Merge the Tools! HackerRank Python Solution

``````# ========================
#       Information
# ========================

# Name: Merge the Tools! in Python HackerRank
# Difficulty: Medium
# Max Score: 40
# Language: Pypy 3

# ========================
#         Solution Start
# ========================

# Merge the Tools! in Python - Hacker Rank Solution

def merge_the_tools(string, k):
temp = []
len_temp = 0
for item in string:
len_temp += 1
if item not in temp:
temp.append(item)
if len_temp == k:
print (''.join(temp))
temp = []
len_temp = 0

if __name__ == '__main__':
string, k = input(), int(input())
merge_the_tools(string, k)

#Merge the Tools! in Python - Hacker Rank Solution END
# MyEduWaves``````

Disclaimer: The above Problem ( Python Merge the Tools! ) is generated by Hackerrank but the Solution is Provided by MyEduWaves. This tutorial is only for Educational and Learning purposes. Authority if any queries regarding this post or website fill out the contact form.

I hope you have understood the solution to this HackerRank Problem. All these three solutions will pass all the test cases. Now visit Merge the Tools in Python Hackerrank Problem and try to solve it again.

All the Best!